regular expressions with the Cyrillic alphabet?

c# regex latin
amateur picture amateur · Feb 16, 2013 · Viewed 12.4k times · Source

I am currently writing some validation that will validate inputted data. I am using regular expressions to do so, working with C#.

Password = @"(?!^[0-9]*$)(?!^[a-zA-Z]*$)^([a-zA-Z0-9]{6,18})$"

Validate Alpha Numeric = [^a-zA-Z0-9ñÑáÁéÉíÍóÓúÚüÜ¡¿{0}]

The above work fine on the latin alphabet, but how can I expand such to working with the Cyrillic alphabet?

Answer

Sergey Kalinichenko picture Sergey Kalinichenko · Feb 16, 2013

The basic approach to covering ranges of characters using regular expressions is to construct an expression of the form [A-Za-z], where A is the first letter of the range, and Z is the last letter of the range.

The problem is, there is no such thing as "The" Cyrillic alphabet: the alphabet is slightly different depending on the language. If you would like to cover Russian version of the Cyrillic, use [А-Яа-я]. You would use a different range, say, for Serbian, because the last letter in their Cyrillic is Ш, not Я.

Another approach is to list all characters one-by-one. Simply find an authoritative reference for the alphabet that you want to put in a regexp, and put all characters for it into a pair of square brackets:

[АБВГДЕЁЖЗИЙКЛМНОПРСТУФХЦЧШЩЪЫЬЭЮЯабвгдеёжзийклмнопрстуфхцчшщъыьэюя]

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