I am having some trouble to achieve this little round robin project. What i try to do is to generate a preview calendar of games
then I want to output;
day 1: Team 1 vs Team 2; Team 3 vs Team 4; Team 5vs Team 6;
day 2 Team 1 vs Team 4; Team 6 vs Team 3; Team 2 vs Team 5;
till the end of the championship;
Here is the code i've got so far but i'm having trouble to let the first team fixed while the rest of the array rotates...:
static void Main(string[] args)
{
string[] ListTeam = new string[] {"Equipe1", "Equipe2", "Equipe3", "Equipe4", "Equipe5", "Equipe6"};
IList<Match> ListMatch = new List<Match>();
it NumberOfDays = (ListTeam.Count()-1);
int y = 2;
for (int i = 1; i <= NumberOfDays; i++)
{
Console.WriteLine("\nDay {0} : \n",i);
Console.WriteLine(ListTeam[0].ToString() + " VS " + ListTeam[i].ToString());
for (y =ListTeam.Count(); y>0 ; y--)
{
Console.WriteLine(ListTeam[y].ToString() + " VS " + ListTeam[y+1].ToString());
y++;
}
}
}
EDIT: I found a code sample in java but i cant translate it...
This should be easy enough to do using modular arithmetic:
UPDATE 2: (As promised correct algorithm)
public void ListMatches(List<string> ListTeam)
{
if (ListTeam.Count % 2 != 0)
{
ListTeam.Add("Bye");
}
int numDays = (numTeams - 1);
int halfSize = numTeams / 2;
List<string> teams = new List<string>();
teams.AddRange(ListTeam.Skip(halfSize).Take(halfSize));
teams.AddRange(ListTeam.Skip(1).Take(halfSize -1).ToArray().Reverse());
int teamsSize = teams.Count;
for (int day = 0; day < numDays; day++)
{
Console.WriteLine("Day {0}", (day + 1));
int teamIdx = day % teamsSize;
Console.WriteLine("{0} vs {1}", teams[teamIdx], ListTeam[0]);
for (int idx = 1; idx < halfSize; idx++)
{
int firstTeam = (day + idx) % teamsSize;
int secondTeam = (day + teamsSize - idx) % teamsSize;
Console.WriteLine("{0} vs {1}", teams[firstTeam], teams[secondTeam]);
}
}
}
which would print each day's team matches.
Let me quickly try to explain how the algorithm works:
I noticed that since we are rotating all the teams except the first one, if we put all the teams in an array except the first one, then we should just read off the first team from that array using index offset based on the day and doing modular arithmetic to wrap around correctly. In practice we would be treating that array as infinitely repeating in both directions and we would be sliding our view incrementally to right (or to the left).
There is one snag, however, and that is the fact that we have to order the teams in a very particular way for this to work correctly. Otherwise, we do not get the correct rotation. Because of this we need to read of the matching second team in a very peculiar way as well.
The correct way to prepare your list is as follows:
Now, the correct way to read off the list is as follow:
1
.(day + idx) % numDays
), we would normally match it with the team that is offset by half the number of teams minus 1 (minus 1 because we dealt with the first match ourselves). However, since the second half of our list was prepared by reverting, we need to match that offset in the reverted second half of the list. A simpler way to do is to observe that in this is equivalent to matching the same index but from the end of the list. Given the current day
offset that is (day + (numDays - idx)) % numDays
.UPDATE 3: I was not happy that my solution involved such convoluted selection, matching, reversing of array elements. After I got thinking about what my solution involved I realized that I was too hung up about keep the order of the teams as given. However, that is not a requirement and one can get a different but equally valid schedule by not caring about the initial ordering. All that matters is the selection algorithm I describe in the second part of my explanation.
Thus you can simplify the following lines:
teams.AddRange(ListTeam.Skip(halfSize).Take(halfSize));
teams.AddRange(ListTeam.Skip(1).Take(halfSize -1).ToArray().Reverse());
to:
teams.AddRange(ListTeam); // Copy all the elements.
teams.RemoveAt(0); // To exclude the first team.