How to serialize/deserialize to `Dictionary<int, string>` from custom XML not using XElement?

myWallJSON picture myWallJSON · Sep 23, 2012 · Viewed 180.7k times · Source

Having empty Dictionary<int, string> how to fill it with keys and values from XML like

<items>
<item id='int_goes_here' value='string_goes_here'/>
</items>

and serialize it back into XML not using XElement?

Answer

L.B picture L.B · Sep 23, 2012

With the help of a temporary item class

public class item
{
    [XmlAttribute]
    public int id;
    [XmlAttribute]
    public string value;
}

Sample Dictionary:

Dictionary<int, string> dict = new Dictionary<int, string>()
{
    {1,"one"}, {2,"two"}
};

.

XmlSerializer serializer = new XmlSerializer(typeof(item[]), 
                                 new XmlRootAttribute() { ElementName = "items" });

Serialization

serializer.Serialize(stream, 
              dict.Select(kv=>new item(){id = kv.Key,value=kv.Value}).ToArray() );

Deserialization

var orgDict = ((item[])serializer.Deserialize(stream))
               .ToDictionary(i => i.id, i => i.value);

------------------------------------------------------------------------------

Here is how it can be done using XElement, if you change your mind.

Serialization

XElement xElem = new XElement(
                    "items",
                    dict.Select(x => new XElement("item",new XAttribute("id", x.Key),new XAttribute("value", x.Value)))
                 );
var xml = xElem.ToString(); //xElem.Save(...);

Deserialization

XElement xElem2 = XElement.Parse(xml); //XElement.Load(...)
var newDict = xElem2.Descendants("item")
                    .ToDictionary(x => (int)x.Attribute("id"), x => (string)x.Attribute("value"));