How do I convert an ISO8601 TimeSpan to a C# TimeSpan?

Codeman picture Codeman · Sep 17, 2012 · Viewed 24.9k times · Source

I am getting a System.FormatException when I try to do the following (as an example):

TimeSpan ts = XmlConvert.ToTimeSpan("P72H");

I've investigated the ISO8601 Standard and it seems to be correct, but I cannot get it to parse hours without throwing an exception, no matter what I do.

Thanks!

EDIT:

Exception detail:

System.FormatException was unhandled by user code
HResult=-2146233033
Message=The string 'P72H' is not a valid TimeSpan value.
Source=System.Xml

Answer

pstrjds picture pstrjds · Sep 17, 2012

You need to add the Time separator to your string. Try this:

TimeSpan ts = XmlConvert.ToTimeSpan("PT72H");

See the duration specification - http://www.w3.org/TR/xmlschema-2/#duration

3.2.6.1 Lexical representation
The lexical representation for duration is the [ISO 8601] extended format PnYn MnDTnH nMnS, where nY represents the number of years, nM the number of months, nD the number of days, 'T' is the date/time separator, nH the number of hours, nM the number of minutes and nS the number of seconds. The number of seconds can include decimal digits to arbitrary precision.

Edit/Update based on comments

As there was some question as to why the string P2M2W5D would not be considered a valid TimeSpan since W is part of the ISO 8601 standard, I wanted to add this update so that if someone runs across that issue they don't have to read through the comments to get the answer. The issue, both for the original string in question P72H and P2M2W5D is that the string must conform to the W3C XML Schema (see the documentation for XmlConvert.ToTimeSpan). When we look at the W3C XML Schema (link above), it references back to the ISO 8601 standard, and in particular to section 5.5.3.2.1 which gives the reason why W is not a valid character in the XML Schema:

Since weeks have no defined carry-over point (52 or 53), weeks should not be used in these applications