XElement and List<T>

Jagd picture Jagd · Jul 14, 2009 · Viewed 7.1k times · Source

I have a class that has the following properties:

public class Author {
  public string FirstName { get; set; }
  public string LastName { get; set; }
}

Next, I have a List of Authors like so:

List<Author> authors = new List<Author> ();

authors.add(
  new Author { 
    FirstName = "Steven",
    LastName = "King"
  });

authors.add(
  new Author { 
    FirstName = "Homer",
    LastName = ""
  });

Now, I am trying to use Linq to XML in order to generate the XML representing my Authors List.

new XElement("Authors",
  new XElement("Author", 
    from na in this.Authors
    select new XElement("First", na.First)))

The block above does not generate the XML as I expect it to. What I get is:

<Authors>
  <Author>
    <First>Steven</First>
    <First>Homer</First>
  </Author>
<Authors>

What I want the XML output to look like is:

<Authors>
  <Author>
    <First>Steven</First>
    <Last>King</Last>
  </Author>
  <Author>
    <First>Homer</First>
    <Last></Last>
  </Author>
</Authors>

Any help on how to get the XML to look as I need it to would be immensely appreciated!

Answer

casperOne picture casperOne · Jul 14, 2009

You need to pass the IEnumerable<XElement> query as the second parameter, not the "Author" string, like so:

// Note the new way to initialize collections in C# 3.0.
List<Author> authors = new List<Author> ()
{
  new Author { FirstName = "Steven", LastName = "King" }),
  new Author { FirstName = "Homer", LastName = "" })
};

// The XML
XElement xml = new XElement("Authors",
    from na in this.Authors
    select new XElement("Author",
        new XElement("First", na.FirstName),
        new XElement("Last", na.LastName)));

That will give you the result you need.