...
for /F %%F in ('dir /B %* 2> nul') do (
...
What I'm attempting to do here is discard the err output of the command (and loop over the stdout output). However, it complains:
2> was unexpected at this time.
Is this some way to achieve this?
in this case you need to escape the > like this
for /F %%F in ('dir /B %* 2^> nul') do (