Remove leading zeros in batch file
In my application, I get a number having leading zeros. I am trying to trim the leading zeros and get the actual number. I tried using /a switch which considers right side of the assignment as an arithmetic expression. So I tried:
SET /a N = 00027
The above gave me the output of 23 which is the decimal equivalent of octal number 27. Then I found this solution online.
SET N = 00027
SET /a N = 1%N%-(11%N%-1%N%)/10
This seems working and is giving the output 27. Is there much easier way to trim the leading zeros in a batch file?
Answer
The method you found is very good. It supports numbers up to 99,999,999 and is very fast.
There is a simpler way to use SET /A that works with numbers up to 9999. It uses the modulus operation. The method cannot be extended to larger numbers.
set n=0027
set /a n=10000%n% %% 10000
The FOR /F method that Dale posted works with "any" size number (up to 8191 digits). However, it needs just a bit more work to handle zero values.
set n=000000000000000000000000000000000000000000000000000027
for /f "tokens=* delims=0" %%N in ("%n%") do set "n=%%N"
if not defined n set "n=0"