Compare output rather than command

bash string-comparison
moztech picture moztech · Jan 9, 2012 · Viewed 49.8k times · Source

Trying to create a script to read a remote file and check the md5 checksum and alert if a mismatch yet getting an error I can't understand.

#!/bin/sh
REMOTEMD5=$(ssh user@host 'md5sum file.txt')
LOCALMD5=$(md5sum 'file.txt')
if [$LOCALMD5 !== $REMOTEMD5]
then
  echo "all OK"
else
  echo -e "no match, Local:"$LOCALMD5"\nRemote:"$REMOTEMD5
fi

This returns line 4: [6135222a12f06b2dfce6a5c1b736891e: command not found

I've tried using ' or " around the $LOCALMD5 but never seem able to get this to compare the outputs. What am I doing wrong? Thanks

Answer

Joachim Isaksson picture Joachim Isaksson · Jan 9, 2012

Try;

if [ "$LOCALMD5" == "$REMOTEMD5" ]

which should work better.

Edit: I think you got == and != reversed in your code.

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