How to do date calculations in Shell Scripting?

bash shell date-arithmetic
cfrederich picture cfrederich · Jun 20, 2011 · Viewed 10.7k times · Source

I have a shell script that runs every night to backup my EC2 sites database and html to S3, and when it backs the folders up, it appends the date to it for easier viewing. But I want it to also be able to delete the relevant backup folders from 3 days before. How can I do the calculations to get the date 3 days ago?

#!/bin/bash
DATE=`date +%m%d%Y`

s3cmd put -r /var/lib/mysql/mydb/ s3://mybucket/mydb-$DATE/
s3cmd put -r /home/ec2-user/public_html/ s3://mybucket/public_html-$DATE/
s3cmd del -r s3://mybucket/mydb-(date 3 days ago)

Answer

J.C. Yamokoski picture J.C. Yamokoski · Jun 20, 2011

You can use the -d flag for the date command:

-d, --date=STRING
     display time described by STRING, not 'now'

So, just change your date variable to:

DATE=`date +%m%d%Y -d "3 days ago"`

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