I'm trying to prevent bash
from saving duplicate commands to my history. Here's what I've got:
shopt -s histappend
export HISTIGNORE='&:ls:cd ~:cd ..:[bf]g:exit:h:history'
export HISTCONTROL=erasedups
export PROMPT_COMMAND='history -a'
This works fine while I'm logged in and .bash_history
is in memory. For example:
$ history
1 vi .bashrc
2 vi .alias
3 cd /cygdrive
4 cd ~jplemme
5 vi .bashrc
6 vi .alias
$ vi .bashrc
$ history
1 vi .alias
2 cd /cygdrive
3 cd ~jplemme
4 vi .alias
5 vi .bashrc
$ vi .alias
$ history
1 cd /cygdrive
2 cd ~jplemme
3 vi .bashrc
4 vi .alias
$ exit
But when I log back in, my history file looks like this:
$ history
1 vi .bashrc
2 vi .alias
3 cd /cygdrive
4 cd ~jplemme
5 vi .bashrc
6 vi .alias
7 vi .bashrc
8 vi .alias
What am I doing wrong?
EDIT: Removing the shopt
and PROMPT_COMMAND
lines from .bashrc
does not fix the problem.
As far as I know, it is not possible to do what you want. I see this as a bug in bash's history processing that could be improved.
export HISTCONTROL=ignoreboth:erasedups # no duplicate entries
shopt -s histappend # append history file
export PROMPT_COMMAND="history -a" # update histfile after every command
This will keep the in memory history unique, but while it does saves history from multiple sessions into the same file, it doesn't keep the history in the file itself unique. history -a
will write the new command to the file unless it's the same as the one immediately before it. It will not do a full de-duplication like the erasedups
setting does in memory.
To see this silliness in action, start a new terminal session, examine the history, and you'll see repeated entries, say ls
. Now run the ls
command, and all the duplicated ls
will be removed from the history in memory, leaving only the last one. The in memory history becomes shorter as you run commands that are duplicated in the history file, yet the history file itself continues to grow.
I use my own script to clean up the history file on demand.
# remove duplicates while preserving input order
function dedup {
awk '! x[$0]++' $@
}
# removes $HISTIGNORE commands from input
function remove_histignore {
if [ -n "$HISTIGNORE" ]; then
# replace : with |, then * with .*
local IGNORE_PAT=`echo "$HISTIGNORE" | sed s/\:/\|/g | sed s/\*/\.\*/g`
# negated grep removes matches
grep -vx "$IGNORE_PAT" $@
else
cat $@
fi
}
# clean up the history file by remove duplicates and commands matching
# $HISTIGNORE entries
function history_cleanup {
local HISTFILE_SRC=~/.bash_history
local HISTFILE_DST=/tmp/.$USER.bash_history.clean
if [ -f $HISTFILE_SRC ]; then
\cp $HISTFILE_SRC $HISTFILE_SRC.backup
dedup $HISTFILE_SRC | remove_histignore >| $HISTFILE_DST
\mv $HISTFILE_DST $HISTFILE_SRC
chmod go-r $HISTFILE_SRC
history -c
history -r
fi
}
I'd love to hear more elegant ways to do this.
Note: the script won't work if you enable timestamp in history via HISTTIMEFORMAT.
Bash can improve the situation by
history -a
to only write new data if it does not match any history in memory, not just the last one.erasedups
setting is set . A simple history -w
in a new terminal would then clean up the history file instead of the silly script above.