Get just the filename from a path in a Bash script
How would I get just the filename without the extension and no path?
The following gives me no extension, but I still have the path attached:
source_file_filename_no_ext=${source_file%.*}
Answer
Most UNIX-like operating systems have a basename executable for a very similar purpose (and dirname for the path):
pax> a=/tmp/file.txt
pax> b=$(basename $a)
pax> echo $b
file.txt
That unfortunately just gives you the file name, including the extension, so you'd need to find a way to strip that off as well.
So, given you have to do that anyway, you may as well find a method that can strip off the path and the extension.
One way to do that (and this is a bash-only solution, needing no other executables):
pax> a=/tmp/xx/file.tar.gz
pax> xpath=${a%/*}
pax> xbase=${a##*/}
pax> xfext=${xbase##*.}
pax> xpref=${xbase%.*}
pax> echo;echo path=${xpath};echo pref=${xpref};echo ext=${xfext}
path=/tmp/xx
pref=file.tar
ext=gz
That little snippet sets xpath (the file path), xpref (the file prefix, what you were specifically asking for) and xfext (the file extension).