In bash
I am trying to glob
a list of files from a directory to give as input to a program. However I would also like to give this program the list of filenames
files="/very/long/path/to/various/files/*.file"
So I could use it like that.
prompt> program -files $files -names $namelist
If the glob
gives me :
/very/long/path/to/various/files/AA.file /very/long/path/to/various/files/BB.file /very/long/path/to/various/files/CC.file /very/long/path/to/various/files/DD.file /very/long/path/to/various/files/ZZ.file
I'd like to get the list of AA BB CC DD ZZ to feed my program without the long pathname and file extension. However I have no clue on how start there ! Any hint much appreciated !
It's better to use an array to hold the filenames. A string variable will not handle filenames which contain spaces.
Also, you don't need to use the basename
command. Instead use bash's built-in string manipulation.
Try this:
files=( /very/long/path/to/various/files/*.file )
for file in "${files[@]}"
do
filename="${file##*/}"
filenameWithoutExtension="${filename%.*}"
echo "$filenameWithoutExtension"
done