Commenting in a Bash script inside a multiline command

Question

How can I comment on each line of the following lines from a script?

cat ${MYSQLDUMP} | \
sed '1d' | \
tr ",;" "\n" | \
sed -e 's/[asbi]:[0-9]*[:]*//g' -e '/^[{}]/d' -e 's/""//g' -e '/^"{/d' | \
sed -n -e '/^"/p' -e '/^print_value$/,/^option_id$/p' | \
sed -e '/^option_id/d' -e '/^print_value/d' -e 's/^"\(.*\)"$/\1/' | \
tr "\n" "," | \
sed -e 's/,\([0-9]*-[0-9]*-[0-9]*\)/\n\1/g' -e 's/,$//' | \
sed -e 's/^/"/g' -e 's/$/"/g' -e 's/,/","/g' >> ${CSV}

If I try and add a comment like:

cat ${MYSQLDUMP} | \ # Output MYSQLDUMP File

I get:

#: not found

Is it possible to comment here?

Answer 1

This will have some overhead, but technically it does answer your question:

echo abc `#Put your comment here` \
     def `#Another chance for a comment` \
     xyz, etc.

And for pipelines specifically, there is a clean solution with no overhead:

echo abc |        # Normal comment OK here
     tr a-z A-Z | # Another normal comment OK here
     sort |       # The pipelines are automatically continued
     uniq         # Final comment

See Stack Overflow question How to Put Line Comment for a Multi-line Command.