In Bash I can write the following test
[[ "f" > "a" ]]
which results in returning 0, i.e. true. How does bash actually perform this string comparison? From my understanding >
does an integer comparison. Does it try to compare the ASCII value of the operands?
From help test
:
STRING1 > STRING2
True if STRING1 sorts after STRING2 lexicographically.
Internally, bash either uses strcoll()
or strcmp()
for that:
else if ((op[0] == '>' || op[0] == '<') && op[1] == '\0')
{
if (shell_compatibility_level > 40 && flags & TEST_LOCALE)
return ((op[0] == '>') ? (strcoll (arg1, arg2) > 0) : (strcoll (arg1, arg2) < 0));
else
return ((op[0] == '>') ? (strcmp (arg1, arg2) > 0) : (strcmp (arg1, arg2) < 0));
}
The latter actually compares ASCII codes, the former (used when locale is enabled) performs a more specific comparison which is suitable for sorting in given locale.