How far can the j(jump) instruction jump in memory? (MIPS)

assembly mips mips32
user977154 picture user977154 · Mar 7, 2012 · Viewed 7.8k times · Source

Consider the j(jump) instruction in MIPS. How far can it jump in memory? Would it be 32bits? Can i please have an explanation.

Answer

Carl Norum picture Carl Norum · Mar 7, 2012

From this page, you'll see that the jump instruction has the following effects:

PC = nPC; nPC = (PC & 0xf0000000) | (target << 2);

target is a 26 bit number. That means the j instruction can jump to any absolute address that can be created from the operation above. The largest value for target, therefore, is 226-1 (0x03FFFFFF), and the highest reachable address is (PC & 0xF0000000) | 0x0FFFFFFC.

Related questions

MIPS assembly for a simple for loop

I need to translate this C code to MIPS assembly. Here is the C code: int tmp = 0; for (int j = 0; j < 15; ++j) tmp = tmp * 2 + 3 This is my MIPS assembly code. Is it a correct translation? If you see any …

Read More
Multiplication using Logical shifts in MIPS assembly

Can someone please give me pointers on how I can go about making a code that multiplies using shifts in MIPS assembly? I don't understand how having a number 2^n can help me multiply using an odd multiplicand I currently …

Read More
what does .space do in mips?

I got this problem for an assignment in which we have put these number in an array and add them without using a loop. I have solved this problem but .space is confusing me. By making .space 20 do i make …

Read More