I am learning assembly language (specific to x86). I have understood that the
SAL
and SHL
works in similar way (clearing the lsb and carrying the msb to CF) from here Difference between SHL and SAL in 80x86.
Considering that SHR
and SAR
doesn't operate in similar way (the latter keeping the msb unchanged).
I would like to have a clear concept about why the functionality of Shift Arithmetic Right SAR
is defined different from Shift Right SHR
but at the same time the SHL
and SAL
are kept with similar functionality ?
Because there's nothing to preserve in case of a left shift. In those cases that a left shift changes the sign (which you might have wanted to prevent somehow), the result without overflow would not fit in a register (this is automatically so - if it did fit, then it wouldn't have overflowed to begin with). So there's nothing you can do about it anyway.
But right shift can't overflow, it makes the number smaller (or it stays the same). So now you can choose, do I keep the top bit intact or not.