In mongodb there are documents in the following structure:
{
"_id" : ObjectId("52d017d4b60fb046cdaf4851"),
"dates" : [
1399518702000,
1399126333000,
1399209192000,
1399027545000
],
"dress_number" : "4",
"name" : "J. Evans",
"numbers" : [
"5982",
"5983",
"5984",
"5985"
]
}
Is it possible unwind data from multiple arrays and get only paired elements from arrays:
{
"dates": "1399518702000",
"numbers": "5982"
},
{
"dates": "1399126333000",
"numbers": "5983"
},
{
"dates": "1399209192000",
"numbers": "5984"
},
{
"dates": "1399027545000",
"numbers": "5985"
}
From version 3.2 you can do it with $unwind
on both of the arrays, $cmp
the indexes, and $match
only the equal indexes.
This solution will populate what you wrote in case you have only the example document. If you have more documents I don't know what you expect to get in the output, but it's solvable by grouping by _id of the document.
db.test.aggregate([
{
$unwind: {
path: '$dates',
includeArrayIndex: 'dates_index',
}
},
{
$unwind: {
path: '$numbers',
includeArrayIndex: 'numbers_index',
}
},
{
$project: {
dates: 1,
numbers: 1,
compare: {
$cmp: ['$dates_index', '$numbers_index']
}
}
},
{
$match: {
compare: 0
}
},
{
$project: {
_id: 0,
dates: 1,
numbers: 1
}
}
])