In Bash, what is the simplest way to test if an array contains a certain value?
This approach has the advantage of not needing to loop over all the elements (at least not explicitly). But since array_to_string_internal()
in array.c still loops over array elements and concatenates them into a string, it's probably not more efficient than the looping solutions proposed, but it's more readable.
if [[ " ${array[@]} " =~ " ${value} " ]]; then
# whatever you want to do when array contains value
fi
if [[ ! " ${array[@]} " =~ " ${value} " ]]; then
# whatever you want to do when array doesn't contain value
fi
Note that in cases where the value you are searching for is one of the words in an array element with spaces, it will give false positives. For example
array=("Jack Brown")
value="Jack"
The regex will see "Jack" as being in the array even though it isn't. So you'll have to change IFS
and the separator characters on your regex if you want still to use this solution, like this
IFS=$'\t'
array=("Jack Brown\tJack Smith")
unset IFS
value="Jack"
if [[ "\t${array[@]}\t" =~ "\t${value}\t" ]]; then
echo "true"
else
echo "false"
fi
This will print "false".
Obviously this can also be used as a test statement, allowing it to be expressed as a one-liner
[[ " ${array[@]} " =~ " ${value} " ]] && echo "true" || echo "false"