I'm using bash and trying to add all elements of an array that was created from a file.
while read line; do
array=($line);
sum=0
length=${#array[@]}
for i in ${array[@]:0:$length}; do
sum=$[$sum+${array[i]}] #<--- this doesn't work?
done
echo $sum
done < $1
edit: I should have been clearer why i want to use array splitting in for loop
The input may be ------> david 34 28 9 12
And I want to print ---> david 83
So I would like to loop through all elements accept the first one. so i would use:
length=$[${#array[@]} - 1]
for i in${array[@]:1:$length}
because of this i can't use:
for i in "${array[@]}"
Try using expr to add two expression something like:
sum=$(expr "$sum" + "${arr[i]}")
Or
sum=$((sum + arr[i]))
echo "11 13" >test.txt
echo "12" >>test.txt
while read -a line; do ##read it as array
sum=0
for ((i=1; i < ${#line}; i++)); do ##for every number in line
sum=$(expr "$sum" + "${line[i]}") ## add it to sum
done
echo $line[0] $sum ##print sum
done < test.txt
Output
36
After OP's edit:
echo "ABC 11 13" >test.txt echo "DEF 12" >>test.txt
while read -a line; do ##read it as array
sum=0
for ((i=1; i < $((${#line[@]})); i++)); do ##for every number in line
sum=$(expr "$sum" + "${line[i]}") ## add it to sum
if [[ $i -eq $((${#line[@]}-1)) ]]
then
echo "${line[0]} $sum" ##print sum
sum=0
fi
done
done < test.txt
Output:
ABC 24
DEF 12