I'm newbie in Go. This issue is driving me nuts. How do you init array of structs in Go?
type opt struct {
shortnm char
longnm, help string
needArg bool
}
const basename_opts []opt {
opt {
shortnm: 'a',
longnm: "multiple",
needArg: false,
help: "Usage for a"}
},
opt {
shortnm: 'b',
longnm: "b-option",
needArg: false,
help: "Usage for b"}
}
The compiler said it expecting ;
after []opt
.
Where should I put the braces {
to init my array of struct?
It looks like you are trying to use (almost) straight up C code here. Go has a few differences.
const
. The term const
has a different meaning in Go, as it does in C. The list should be defined as var
instead.basenameOpts
as opposed to basename_opts
.char
type in Go. You probably want byte
(or rune
if you intend to allow unicode codepoints).var x = foo
.For example:
type opt struct {
shortnm byte
longnm, help string
needArg bool
}
var basenameOpts = []opt {
opt {
shortnm: 'a',
longnm: "multiple",
needArg: false,
help: "Usage for a",
},
opt {
shortnm: 'b',
longnm: "b-option",
needArg: false,
help: "Usage for b",
},
}
An alternative is to declare the list with its type and then use an init
function to fill it up. This is mostly useful if you intend to use values returned by functions in the data structure. init
functions are run when the program is being initialized and are guaranteed to finish before main
is executed. You can have multiple init
functions in a package, or even in the same source file.
type opt struct {
shortnm byte
longnm, help string
needArg bool
}
var basenameOpts []opt
func init() {
basenameOpts = []opt{
opt {
shortnm: 'a',
longnm: "multiple",
needArg: false,
help: "Usage for a",
},
opt {
shortnm: 'b',
longnm: "b-option",
needArg: false,
help: "Usage for b",
},
}
}
Since you are new to Go, I strongly recommend reading through the language specification. It is pretty short and very clearly written. It will clear a lot of these little idiosyncrasies up for you.