Shape drawable as background, a line at the bottom

Question

I am using a drawable as a background of a TextView just to have a divider line below the text. A achivied it with this drawable-xml:

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
    <item>
        <shape 
        android:shape="rectangle">
            <solid android:color="#FFDDDDDD" />
            <gradient 
                android:angle="0"
                android:startColor="#FFAAAAAA"
                android:endColor="#FFEEEEEE"
                />
        </shape>
    </item>

    <item android:bottom="2dp">
        <shape 
        android:shape="rectangle">
            <solid android:color="#FF000000" />
        </shape>
    </item>

</layer-list>

But this method draws a colored rectangle above a black rectangle. I would like to have just the line at the bottom of the shape with no black rectangle because black is not transparent. How could I achieve that?

Answer 1

This is how I got a line at the bottom for mine. Draw a stroke but then shift the item up and to the sides to get the top and sides to not show the stroke:

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:top="-8dp" android:left="-8dp" android:right="-8dp">
        <shape> 
            <solid android:color="#2b7996"/>
            <stroke android:color="#33b5e5" android:width="6dp"/>
        </shape>
    </item>
</layer-list>