I have a gallery that shows an array of images, when clicked they are displayed in an imageview. I want to be able to SHARE the image that is currently being displayed in an intent chooser. I can't figure out how to select the current image.
Gallery code:
public View getView(int position, View convertView, ViewGroup parent) {
ImageView imageView = new ImageView(mContext);
imageView.setImageResource(mImageIds[position]);
imageView.setLayoutParams(new Gallery.LayoutParams(150, 120));
imageView.setScaleType(ImageView.ScaleType.FIT_XY);
imageView.setBackgroundResource(mGalleryItemBackground);
return imageView;
}
Intent chooser code:
Intent share = new Intent(Intent.ACTION_SEND);
share.setType("image/png");
share.putExtra(Intent.EXTRA_STREAM,
Uri.parse("android.resource://com.appinfluence.fanapp.v1/drawable/" + Integer.toString(R.drawable.alright)));
startActivity(Intent.createChooser(share, "Share Image"));
Where it says R.drawable.alright I need that to be a variable of the current image somehow. Any ideas?
To fetch currently selected view use
Gallery.getSelectedView();
and for getting Drawable from imageView use:
ImageVIew.getDrawable()
If you want to get inputstream from the drawable use following:
BitmapDrawable bitmapDrawable = ((BitmapDrawable) drawable);
Bitmap bitmap = bitmapDrawable .getBitmap();
ByteArrayOutputStream stream = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.JPEG, 100, stream);
byte[] imageInByte = stream.toByteArray();
ByteArrayInputStream bis = new ByteArrayInputStream(imageInByte);