I plan to use quick actions UI pattern in my application. Android Quick Actions UI Pattern . The quick action window needs a pivot view to stick to.
quickAction.show(View pivotView);
I intend to use quick action for the menu Item, I can get access to the item that is clicked. But the problem is i need to reference a view from the menu item so that i can pass it to the quick action.
How can i get reference to a view in the menuItem that is selected.
You can achieve this by providing your menu item with an actionViewClass property in xml and then you will be able to get the pivot view u wanted. The code would be something like this
<item
android:id="@+id/menu_find"
android:showAsAction="ifRoom"
android:actionViewClass="android.widget.ImageButton"
/>
In your OnCreateOptionsMenu do this
public boolean onCreateOptionsMenu(Menu menu) {
super.onCreateOptionsMenu(menu);
getMenuInflater().inflate(R.menu.menu_search, menu);
locButton = (ImageButton) menu.findItem(R.id.menu_find).getActionView();
locButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
createPopup();
mQuickAction.show(v);
}
});
return true;
}