changing the position of ImageView dynamically in android

android layoutparams
surendra picture surendra · Jul 7, 2011 · Viewed 14.4k times · Source

all

I need to change the position of a ImageView dynamically and iam using the following code

int x=100,y=100;
RelativeLayout.LayoutParams mparam = new RelativeLayout.LayoutParams((int)(LayoutParams.FILL_PARENT),(int)(LayoutParams.FILL_PARENT));
    mparam.topMargin=x;
    mparam.leftMargin=y;
    ball.setLayoutParams(mparam);
    x+=100;
    y+=100;

but i didnt get any change.

Is it possible? and How?

Answer

Gregory Kalabin picture Gregory Kalabin · Jul 7, 2011

You change margin, but not its position and, it seems, it's not a good solution. Try to use method View.layout(int, int, int, int) Documentation says:

public void layout (int l, int t, int r, int b)

Since: API Level 1
Assign a size and position to a view and all of its descendants
This is the second phase of the layout mechanism. (The first is measuring). 
In this phase, each parent calls layout on all of its children to position them. 
This is typically done using the child measurements that were stored in 
the measure pass(). Derived classes should not override this method. Derived 
classes with children should override onLayout. In that method, they should call 
layout on each of their children.

Parameters

l   Left position, relative to parent
t   Top position, relative to parent
r   Right position, relative to parent
b   Bottom position, relative to parent

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