React Native - Native Base Footer not change color

Question

Here is the code:

 // Bottom.js
<StyleProvider style={getTheme(commonColor)}>
    <Footer>
        <FooterTab>
            <Button active>
                <Icon active name="food" size={24}  />
                <Text active>Lunch Box</Text>
            </Button>
            <Button>
                <Icon name="coins" size={24} />
                <Text>Point</Text>
            </Button>
            <Button>
                <Icon name="face" size={24} />
                <Text>Profile</Text>
            </Button>
        </FooterTab>
    </Footer>

</StyleProvider>

// commonColor.js

// Footer
footerHeight: 55,
footerDefaultBg: '#ffffff',

// FooterTab
tabBarTextColor: '#FFF',
tabBarTextSize: platform === 'ios' ? 14 : 16,
activeTab: platform === 'ios' ? '#007aff' : '#fff',
sTabBarActiveTextColor: '#007aff',
tabBarActiveTextColor: '#fff',
tabActiveBgColor: platform === 'ios' ? '#1569f4' : '#1569f4',

here is the result:

I've tried edit FooterTab.js directly but no changed at all.

The only changes that can happen on render is tabActiveBgColor: platform === 'ios' ? '#1569f4' : '#1569f4'. And I don't even know why only this code is working, I not even set any active on FooterTab.

What I expected is when I set active the button and text become white.

Any Solution?

Answer 1

I have solved this issue for adding style in FooterTab.You do not need to do any styling in native base Footer component.Here is my source code-

     <Footer>
          <FooterTab style={{backgroundColor:"#FFF"}}>
              <Button style={{paddingLeft:0, paddingRight:0}}>
                  <Text}}>iFeeds</Text>
              </Button>
              <Button style={{paddingLeft:0, paddingRight:0}}>
                  <Text}}>iFeeds</Text>
              </Button>
          </FooterTab>
    <Footer>