Android: When using setOnCheckedChangeListener on switches I get 'Cannot Resolve Symbol Error'

Koustav Samaddar picture Koustav Samaddar · Apr 24, 2015 · Viewed 14.4k times · Source
package com.example.koustav.myapplication;

import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.widget.Switch;
import android.widget.TextView;
import android.widget.CompoundButton;
import android.widget.CompoundButton.OnCheckedChangeListener;

public class MainActivity extends Activity
{

    @Override
    protected void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
    }

    Switch swi = (Switch) findViewById(R.id.swch);
    swi.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener()
    {
        public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) //Line A
        {

        }
    });

    public void onClick(View view)
    {
        boolean isOn = ((Switch) view).isChecked();

        if (isOn)
        {
            ((TextView) findViewById(R.id.largey)).setTextColor(getResources().getColor(R.color.black));
        }
        else
        {
            ((TextView) findViewById(R.id.largey)).setTextColor(getResources().getColor(R.color.white));
        }

    }

}

I am using Android Studio for this project. I have searched the interwebs for a solution extensibly but could not find one.

I have been trying to use setOnCheckedChangeListener for a Switch object. However no matter what I try, I always get a Cannot Resolve Symbol 'setOnCheckedChangeListener' error. Also, at the line A, the object buttonView is underlined red giving the same error Cannot Resolve Symbol 'buttonView'.

I have imported the necessary (and recommended as answers for other people) classes. I am working with APIs for android 4.0 and above. I basically want the onClick method to be re-implemented via the listener because the listener works with both clicks and swipes whereas onClick only works with clicks and not swipes.

Answer

Mohit Rajput picture Mohit Rajput · Apr 24, 2015

You have to initialize Switch inside onCreate()