I have application A defined as below:
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name="com.example.MyExampleActivity"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
Now in application B, how can I write the code to start the activity in application A? Thanks!
If you guys are facing "Permission Denial: starting Intent..." error or if the app is getting crash without any reason during launching the app - Then use this single line code in Manifest
android:exported="true"
Please be careful with finish(); , if you missed out it the app getting frozen. if its mentioned the app would be a smooth launcher.
finish();
The other solution only works for two activities that are in the same application. In my case, application B doesn't know class com.example.MyExampleActivity.class
in the code, so compile will fail.
I searched on the web and found something like this below, and it works well.
Intent intent = new Intent();
intent.setComponent(new ComponentName("com.example", "com.example.MyExampleActivity"));
startActivity(intent);
You can also use the setClassName method:
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setClassName("com.hotfoot.rapid.adani.wheeler.android", "com.hotfoot.rapid.adani.wheeler.android.view.activities.MainActivity");
startActivity(intent);
finish();
You can also pass the values from one app to another app :
Intent launchIntent = getApplicationContext().getPackageManager().getLaunchIntentForPackage("com.hotfoot.rapid.adani.wheeler.android.LoginActivity");
if (launchIntent != null) {
launchIntent.putExtra("AppID", "MY-CHILD-APP1");
launchIntent.putExtra("UserID", "MY-APP");
launchIntent.putExtra("Password", "MY-PASSWORD");
startActivity(launchIntent);
finish();
} else {
Toast.makeText(getApplicationContext(), " launch Intent not available", Toast.LENGTH_SHORT).show();
}