How to show only top and bottom border

Question

This is my XML code which works fine, the only problem is it's showing border on all four sides while I want only to show border on the top and on the bottom only. How can I do that?

<?xml version="1.0" encoding="UTF-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" >

    <solid android:color="#FFFFFF" />
    <stroke
        android:width="3dip"
        android:color="#B1BCBE"
    />

    <padding
        android:bottom="0dip"
        android:left="0dip"
        android:right="0dip"
        android:top="0dip"
    />

</shape>

Answer 1

Try the below

<?xml version="1.0" encoding="utf-8"?>
 <layer-list xmlns:android="http://schemas.android.com/apk/res/android">
  <item> 
    <shape android:shape="rectangle">
      <solid android:color="#FF0000" /> 
    </shape>
  </item>   
    <item android:bottom="5dp"  android:top="5dp" >  
     // add android:right="5dp" and android:left="5dp" for border on left and right
     <shape android:shape="rectangle"> 
      <solid android:color="#000000" />
    </shape>
   </item>    
 </layer-list> 

Edit:

Modify the below according to your requirements by changing the color, stroke width and padding

<?xml version="1.0" encoding="utf-8"?>
  <layer-list xmlns:android="http://schemas.android.com/apk/res/android">
  <item> 
    <shape android:shape="rectangle">
    <stroke
        android:width="5dip"
        android:color="#B1BCBE"
    />
    <padding
        android:bottom="0dip"
        android:left="0dip"
        android:right="0dip"
        android:top="0dip"
    />
    </shape>
  </item>   
    <item android:bottom="5dp"  android:top="5dp" >  
     <shape android:shape="rectangle"> 
      <solid android:color="#FFFFFF" />
    </shape>
   </item>    
 </layer-list>  

Snap