I'm developing an android application and I'm going to use the LVL library to check google play licence.
After reading the LVL documentation, I've read that I have to obtain the android.Settings.Secure.ANDROID_ID to obfuscate the google play responses.
But I've also read that the ANDROID_ID obtained from TelephonyManager is sometimes the same for different devices.
First, it is not 100% reliable on releases of Android prior to 2.2 (“Froyo”). Also, there has been at least one widely-observed bug in a popular handset from a major manufacturer, where every instance has the same ANDROID_ID
Is that true?
Thanks
Consider my case:
Same serial number on several android devices. Adb is useless. How can I change the serial number?
So I did'nt solved the problem with the ADB but to identify an Android device I use this code (use getDeviceId(context)
):
public static String getDeviceId(Context context) {
String id = getUniqueID(context);
if (id == null)
id = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
return id;
}
private static String getUniqueID(Context context) {
String telephonyDeviceId = "NoTelephonyId";
String androidDeviceId = "NoAndroidId";
// get telephony id
try {
final TelephonyManager tm = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
telephonyDeviceId = tm.getDeviceId();
if (telephonyDeviceId == null) {
telephonyDeviceId = "NoTelephonyId";
}
} catch (Exception e) {
}
// get internal android device id
try {
androidDeviceId = android.provider.Settings.Secure.getString(context.getContentResolver(),
android.provider.Settings.Secure.ANDROID_ID);
if (androidDeviceId == null) {
androidDeviceId = "NoAndroidId";
}
} catch (Exception e) {
}
// build up the uuid
try {
String id = getStringIntegerHexBlocks(androidDeviceId.hashCode())
+ "-"
+ getStringIntegerHexBlocks(telephonyDeviceId.hashCode());
return id;
} catch (Exception e) {
return "0000-0000-1111-1111";
}
}
public static String getStringIntegerHexBlocks(int value) {
String result = "";
String string = Integer.toHexString(value);
int remain = 8 - string.length();
char[] chars = new char[remain];
Arrays.fill(chars, '0');
string = new String(chars) + string;
int count = 0;
for (int i = string.length() - 1; i >= 0; i--) {
count++;
result = string.substring(i, i + 1) + result;
if (count == 4) {
result = "-" + result;
count = 0;
}
}
if (result.startsWith("-")) {
result = result.substring(1, result.length());
}
return result;
}
I use it to identify a specific app installation when calling my web services. As you can see I try different approches, based also on TelephonyManager and ANDROID_ID.
What I get is a string like xxxx-xxxx-xxxx-xxxx where x is an hex character.
I bought a lot of low cost China tablets and all of these have the same DEVICE_ID and the same serial number !! So my solution. It's working well for now.