How do I get IP_ADDRESS in IPV4 format

Rahul Baradia picture Rahul Baradia · Jun 13, 2012 · Viewed 33.5k times · Source

I am trying to get the IP address of an device i.e using WIFI or 3G connection. I am getting the ip address in IPV6 format which is not understandable. I want in IPV4 format IP address.I have done google but dint found any proper solutions.

here is code which I am using to get IP address of an device

public String getLocalIpAddress() {
    try {
        try {
        for (Enumeration<NetworkInterface> en = NetworkInterface
                .getNetworkInterfaces(); en.hasMoreElements();) {
            NetworkInterface intf = en.nextElement();
            for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) 
            {
                InetAddress inetAddress = enumIpAddr.nextElement();
                System.out.println("ip1--:" + inetAddress);
                System.out.println("ip2--:" + inetAddress.getHostAddress());
                if (!inetAddress.isLoopbackAddress()) {


                    String ip = inetAddress.getHostAddress().toString();
                    System.out.println("ip---::" + ip);
                    EditText tv = (EditText) findViewById(R.id.ipadd);
                    tv.setText(ip);
                    return inetAddress.getHostAddress().toString();

                }
            }
        }
    } catch (Exception ex) {
        Log.e("IP Address", ex.toString());
    }
    return null;
}

I am getting this ouput :

ip1--:/fe80::5054:ff:fe12:3456%eth0%2
ip2--:fe80::5054:ff:fe12:3456%eth0

It should be displayed like this :

192.168.1.1

please help me out..

Answer

Rahul Baradia picture Rahul Baradia · Jun 14, 2012

After trying many tricks.. finally I can get the IP address in IPV4 format.. Here is my code..

public String getLocalIpAddress() {
    try {
        for (Enumeration<NetworkInterface> en = NetworkInterface
                .getNetworkInterfaces(); en.hasMoreElements();) {
            NetworkInterface intf = en.nextElement();
            for (Enumeration<InetAddress> enumIpAddr = intf
                    .getInetAddresses(); enumIpAddr.hasMoreElements();) {
                InetAddress inetAddress = enumIpAddr.nextElement();
                System.out.println("ip1--:" + inetAddress);
                System.out.println("ip2--:" + inetAddress.getHostAddress());

      // for getting IPV4 format
      if (!inetAddress.isLoopbackAddress() && InetAddressUtils.isIPv4Address(ipv4 = inetAddress.getHostAddress())) {

                    String ip = inetAddress.getHostAddress().toString();
                    System.out.println("ip---::" + ip);
                    EditText tv = (EditText) findViewById(R.id.ipadd);
                    tv.setText(ip);
                    // return inetAddress.getHostAddress().toString();
                    return ip;
                }
            }
        }
    } catch (Exception ex) {
        Log.e("IP Address", ex.toString());
    }
    return null;
}

Added if condition as shown below

 /**This shows IPV4 format IP address*/
 if (!inetAddress.isLoopbackAddress() && InetAddressUtils.isIPv4Address(ipv4 = inetAddress.getHostAddress())){}

instead of this

 /**This shows IPV6 format IP address*/
 if (!inetAddress.isLoopbackAddress()){}

Many Thanks.. Rahul

An alternative for checking if the address is a version 4 address is:

if (!inetAddress.isLoopbackAddress() && inetAddress instanceof Inet4Address)