Tricky Google interview question

Chris Eberle picture Chris Eberle · Mar 31, 2011 · Viewed 30.5k times · Source

A friend of mine is interviewing for a job. One of the interview questions got me thinking, just wanted some feedback.

There are 2 non-negative integers: i and j. Given the following equation, find an (optimal) solution to iterate over i and j in such a way that the output is sorted.

2^i * 5^j

So the first few rounds would look like this:

2^0 * 5^0 = 1
2^1 * 5^0 = 2
2^2 * 5^0 = 4
2^0 * 5^1 = 5
2^3 * 5^0 = 8
2^1 * 5^1 = 10
2^4 * 5^0 = 16
2^2 * 5^1 = 20
2^0 * 5^2 = 25

Try as I might, I can't see a pattern. Your thoughts?

Answer

user515430 picture user515430 · Mar 31, 2011

Dijkstra derives an eloquent solution in "A Discipline of Programming". He attributes the problem to Hamming. Here is my implementation of Dijkstra’s solution.

int main()
{
    const int n = 20;       // Generate the first n numbers

    std::vector<int> v(n);
    v[0] = 1;

    int i2 = 0;             // Index for 2
    int i5 = 0;             // Index for 5

    int x2 = 2 * v[i2];     // Next two candidates
    int x5 = 5 * v[i5];

    for (int i = 1; i != n; ++i)
    {
        int m = std::min(x2, x5);
        std::cout << m << " ";
        v[i] = m;

        if (x2 == m)
        {
            ++i2;
            x2 = 2 * v[i2];
        }
        if (x5 == m)
        {
            ++i5;
            x5 = 5 * v[i5];
        }
    }

    std::cout << std::endl;
    return 0;
}