I am having trouble fully understanding the K-Means++ algorithm. I am interested exactly how the first k
centroids are picked, namely the initialization as the rest is like in the original K-Means algorithm.
I will appreciate a step by step explanation and an example. The one in Wikipedia is not clear enough. Also a very well commented source code would also help. If you are using 6 arrays then please tell us which one is for what.
Interesting question. Thank you for bringing this paper to my attention - K-Means++: The Advantages of Careful Seeding
In simple terms, cluster centers are initially chosen at random from the set of input observation vectors, where the probability of choosing vector x
is high if x
is not near any previously chosen centers.
Here is a one-dimensional example. Our observations are [0, 1, 2, 3, 4]. Let the first center, c1
, be 0. The probability that the next cluster center, c2
, is x is proportional to ||c1-x||^2
. So, P(c2 = 1) = 1a, P(c2 = 2) = 4a, P(c2 = 3) = 9a, P(c2 = 4) = 16a, where a = 1/(1+4+9+16).
Suppose c2=4. Then, P(c3 = 1) = 1a, P(c3 = 2) = 4a, P(c3 = 3) = 1a, where a = 1/(1+4+1).
I've coded the initialization procedure in Python; I don't know if this helps you.
def initialize(X, K):
C = [X[0]]
for k in range(1, K):
D2 = scipy.array([min([scipy.inner(c-x,c-x) for c in C]) for x in X])
probs = D2/D2.sum()
cumprobs = probs.cumsum()
r = scipy.rand()
for j,p in enumerate(cumprobs):
if r < p:
i = j
break
C.append(X[i])
return C
EDIT with clarification: The output of cumsum
gives us boundaries to partition the interval [0,1]. These partitions have length equal to the probability of the corresponding point being chosen as a center. So then, since r
is uniformly chosen between [0,1], it will fall into exactly one of these intervals (because of break
). The for
loop checks to see which partition r
is in.
Example:
probs = [0.1, 0.2, 0.3, 0.4]
cumprobs = [0.1, 0.3, 0.6, 1.0]
if r < cumprobs[0]:
# this event has probability 0.1
i = 0
elif r < cumprobs[1]:
# this event has probability 0.2
i = 1
elif r < cumprobs[2]:
# this event has probability 0.3
i = 2
elif r < cumprobs[3]:
# this event has probability 0.4
i = 3